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Obtain approx. the ratio of the nuclear ...

Obtain approx. the ratio of the nuclear radii of the gold isotope `._79Au^(197)` and silver isotope `._47Ag^(107)`.

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Here,
For `""_(79)Au^(197), A_(1) = 197` and
For `""_(47)Ag^(107), A_(2) -107`
`therefore` Ratio of radii, `R_(1)/R_(2) =(A_(1)/A_(2))^(1/3) = (197/107)^(1/3) =1.23`
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MODERN PUBLICATION-NUCLEI-NCERT FILE SOLVED (TEXTBOOK EXERCISES)
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  2. Obtain the binding energy of the nuclei .26Fe^(56) and .83Bi^(209) in ...

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  9. Obtain approx. the ratio of the nuclear radii of the gold isotope .79A...

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  10. Find the Q value and the kinetic energy of emitted alpha particle in t...

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  12. The nucleus .^(23)Ne deacays by beta-emission into the nucleus .^(23)...

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  14. Suppose, we think of fission of a .26Fe^(56) nucleus into two equal fr...

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  15. The fission properties of .84Pu^(239) are very similar to those of .92...

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  16. A 1000 MW fission reactor consumes half of its fuel in 5.00y. How much...

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  17. How long can an electric lamp of 100W be kept glowing by fusion of 2.0...

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  18. Calculate the height of potential barrier for a head on collision of t...

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  19. from the relation R=R0A^(1//3), where R0 is a constant and A is the ma...

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  20. for the beta^(+) (positron) emission from a nucleus, there is another ...

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