A 1000 MW fission reactor consumes half of its fuel in 5.00y. How much `._92U^(235)` did it contain initially? Assume that the reactor operates `80%` of the time and that all the energy generated arises form the fission of `._92U^(235)` and that this nuclide is consumed by the fission process.

Explanation

Energy generated in fission of 1 g of `""_(92)U^(235)`
`=(6.023 xx 10^(23) xx 200 xx 1.6 xx 10^(-12))/235` J
The amount of `""_(92)U^(235)` consumed in 5 years with 80% of the time.
`=(5 xx 0.8 xx 365 xx 24 xx 6 xx 6 xx 10^(11))/235 xx 235`g
`=1,544.15 xx 10^(3)g = 1,544.15 xx 2= 3,088.3` kg