Home
Class 12
PHYSICS
A piece of wood form the ruins of an an...

A piece of wood form the ruins of an ancient building was found to have a `C^(14)` activity of 12 disintegrations per minute per gram of its carbon content. The `C^(14)` activity of the living wood is 16 disintegrations/minute/gram. How long ago did the trees, from which the wooden sample came, die? Given half-life of `C^(14)` is 5760 years.

Text Solution

Verified by Experts

Given, `t_(1//2)=5760` years.
`R_(0)=16` disintegration per min per gram.
R=12 disintegration per min per gram.
Let t be the time of disintegration. Then,
`t=1/lambda log_(e) R_(0)/R`
Where `lambda` is the decay constant and is given by
`lambda = 0.693/t_(1//2)`
`therefore t=t_(1//2)/0.693 xx 2.303 log _(10)4/3`
`=5760/0.693 xx 2.303 (0.602 - 0.477) = 2392.7` years.
Promotional Banner

Topper's Solved these Questions

  • NUCLEI

    MODERN PUBLICATION|Exercise HIGH ORDER THINKING SKILLS & ADVANCED LEVEL|9 Videos

  • NUCLEI

    MODERN PUBLICATION|Exercise REVISION EXERCISES (VERY SHORT ANSWER QUESTIONS)|47 Videos

  • NUCLEI

    MODERN PUBLICATION|Exercise NCERT FILE SOLVED (NCERT EXEMPLAR PROBLEMS SUBJECTIVE QUESTIONS) (VERY SHORT ANSWER TYPE QUESTIONS)|5 Videos

  • MOVING CHARGES AND MAGNETISM

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|13 Videos

  • RAY OPTICS AND OPTICAL INSTRUMENTS

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|14 Videos

Similar Questions

Explore conceptually related problems

A piece of wood form the ruins of an nuclei an ancient building was found to have a .^(14)C activity of 12 disintegrations per minute per gram of its carbon content. The .^(14)C activity of the living wood is 16 disintegrations/minute/gram. How long ago did the trees, form which the wooden sample came, die? Given half-life of .^(14)C is 5760yers .

A sample of wooden artifact is found to undergo 9 disintegration per minute per gram of carbon. What is the approximate age of the artifact? The half life of ._(6)^(14)C is 5730 years and radioactivity of wood recently cut is 15 disintegrations per minute per gram of carbon.

A piece of ancient wood shows an activity of 3.9 disintergration per sec. per gram of .^(14)C . Calculate the age of the wood. T_(1//2) of .^(14) C=5570 years. Activity of fresh .^(14)C=15.6 disinteration per second per gram.

When charcoal is prepared from a living tree, it shows a disintergration rate of 15.3 disintergrations of ^14C per gram per minute. A sample form an ancient piece of charcoal shows ^14C activity to be 12.3 disintergrations per gram per minute. How old is this sample ? Half-life of ^14C is 5730 y.

It is known that the ratio of .^(14)C to .^(12)C atoms in living beings and atmosphere is a constant. In one experiment it was found that the radiocarbon activity of a living thing is 16 disintegration per minute per gram of carbon content. Find the ratio of .^(14)C to .^(12)C atoms in your body. Half life of beta decay of .^(14)C is 5760yr= 0.03xx10^(9) minute.

A piece of charcoal from the ruins of a settlement in Japan was found to have .^(14)C// .^(14)C ratio what was 0.617 times that found in living organisms. How old is the piece of charcol? ( t_(1//2) for .^(14)C is 5770 year?)

Determine the average .^(14)C activity in decays per minute per gram of natural carbon found in living organisms if the concentration of .^(14)C relative to that of .^(12)C is 1.4 xx10^(-12) and half -life of .^(14)C is T_(1//2)=57.30 years.