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A nuclide 1 is said to be the mirror iso...

A nuclide 1 is said to be the mirror isobar of nuclide 2 if `Z_(1)=N_(2)` and `Z_(2)=N_(1)`. (a) What nuclide is a mirror isobar of `._(11)^(23)Na`? (b) Which nuclide out of the two mirror isobars has greater binding energy and why?

Text Solution

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(a) For nuclei, `""_(11)Na^(23)`
`Z_(1)=11, N_(1)=12`
For `""_(12)Mg^(23)`
`Z_(2) =12, N_(2)=11`
`therefore` Mirror isobar of `""_(11)Na^(23)` is `""_(12)Mg^(23)`
(b) Since, `Z_(2) gt Z_(1)`. Mg has greater binding energy than Na.
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