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Calculate the amount of energy released ...

Calculate the amount of energy released during the `alpha`-decay of
`._(92)^(238)Urarr_(90)^(234)Th+._(2)^(4)He`
Given: atomic mass of `._(92)^(238)U=238.05079 u`, atomic mass of `._(90)^(234)Th=234.04363 u`,
atomic mass `._(2)^(4)He=4.00260u , 1u=931.5 MeV//c^(2)`. Is this decay spontaneous?Give reason.

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Verified by Experts

B.E `=[""^(m)(""_(92)U^(238))-""^(m)(""_(90)Th^(234)) - ""^(m)(""_(2)He^(4))]c^(2)`
`=(238.05079 - 234.04363 - 4.00260)931 MeV`
`=0.0045 xx 931 = 4.24` MeV
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Calculate the energy released in MeV in the following nuclear reaction : ._(92)^(238)Urarr._(90)^(234)Th+._(2)^(4)He+Q ["Mass of "._(92)^(238)U=238.05079 u Mass of ._(90)^(238)Th=234.043630 u Massof ._(2)^(4)He=4.002600 u 1u = 931.5 MeV//c^(2)]

Find energy released in the alpha decay, Given _92^238Urarr_90^234Th+_2^4He M( _92^238U)=238.050784u M( _90^234Th)=234.043593u M( _2^4He)=4.002602u

Alpha decay of ._(92)^(238)U forms ._(90)^(234)Th . What kind of decay from ._(90)^(234)Th produces ._(84)^(234)Ac ?

Calculate the energy released in fusion reaction : 4._(1)^(1)Hto._(2)^(4)He+2._(+1)^(0)e Given : mass of ._(1)^(1)H=1.007825u , mass of ._(2)^(4)He=4.00260 u and 1u=931.5 MeV Neglect the mass of positron (._(+1)^(0)e) .

The radioactive decay of uranium into thorium is represented by the equation: ._(92)^(238)Urarr._(90)^(234)Th+x What is x ?

We are given the following atomic masses: ._(92)^(238)U=238.05079u ._(2)^(4)He=4.00260u ._(90)^(234)Th=234.04363u ._(1)^(1)H=1.00783u ._(91)^(237)Pa=237.05121u Here the symbol Pa is for the element protactinium (Z=91)

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