The mass of proton is `1.0073 u` and that of neutron is `1.0087 u` (`u=` atomic mass unit). The binding energy of `._(2)He^(4)` is (mass of helium nucleus `=4.0015 u`)

Options

A. 0.0305 erg
B. 28.4 MeV
C. 0.061 u
D. 0.0305 J
Given helium nucleus mass =4.0015 u

Answer

B

Explanation

The binding energy of He
B.E. (He) `=[2m_(p) + 2m_(n)-4.0015] xx 931` MeV
`=[2 xx 1.0073 + 2 xx 1.0087 -(4.0015)] xx 931 MeV`
=28.39 MeV