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The binding energy of deuteron is 2.2 Me...

The binding energy of deuteron is `2.2` MeV and that of `._(2)^(4)He` is `28` MeV. If two deuterons are fused to form one `._(2)^(4)He`, th `n` the energy released is

A

30.2 MeV

B

25.8 MeV

C

23.6 MeV

D

19.2 MeV

Text Solution

Verified by Experts

The correct Answer is:
C

`""_(1)H^(2) + ""_(1)H^(2) to ""_(2)He^(4)` + Energy
Energy released = Energy released
`=B.E.(""_(2)He^(4))-2B.E(""_(1)H^(2))`
`=(28 -2 xx 2.2) MeV`
=23.6 MeV
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