The fossil bone has a `.^(14)C` : `.^(12)C` ratio, which is `[(1)/(16)]` of that in a living animal bone. If the half -life of `.^(14)C` is `5730` years, then the age of the fossil bone is :

Options

A. 11,460 years
B. 17,190 years
C. 22,920 years
D. 45,840 yrs

Answer

C

Explanation

The remaining amount of `C^(14)` in bones,
`N/N_(0) =(1/18) =(1/2)^(4) = (1/2)^(n)`
n=4, four half-lives involves, so
`t=nT_(1//2)=4 xx 5,730 = 22,920` yr.