The mass of a .(3)^(7) Li nucleus is 0.0...

The mass of a `._(3)^(7) Li` nucleus is `0.042 u` less than the sum of the masses of all its nucleons. The binding energy per nucleon of `._(3)^(7)Li` nucleus is nearly

A

3.9 MeV

B

26 MeV

C

46 MeV

D

5.6 MeV

Text Solution

Verified by Experts

The correct Answer is:

D

`Deltam=0.042`u
Total nucleon in `""_(3)Li^(7)=3p+4n=7` nucleons
`(B.E.)/n = (Deltam xx 931 MeV)/7`
`=(0.042 xx 931)/7 = 5.6` MeV

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