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If radius of the .(13)^(27)Al nucleus is...

If radius of the `._(13)^(27)Al` nucleus is taken to be `R_(AI)`, then the radius of `._(53)^(125)Te` nucleus is nearly

A

`5/3R_(Al)`

B

`3/5R_(Al)`

C

`(13/53)^(1//3)R_(Al)`

D

`(53/13)^(1//3)R_(Al)`

Text Solution

Verified by Experts

The correct Answer is:
A
`R_(Al)=R_(0)(27)^(1//3) =3R_(0)`
`R_(Te)=R_(0)(125)^(1//3)=5R_(0)`
`R_(Al)/R_(Te)=3/5` `[R_(Te)=5/3R_(Al)]`
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