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The half-life period of a radio-active e...

The half-life period of a radio-active element `X` is same as the mean life time of another radio-active element `Y`. Initially they have the same number of atoms. Then:

A

Y decays faster than X

B

X and Y decay equally initially

C

X and Y decay at same rate always

D

X will decay faster than Y

Text Solution

Verified by Experts

The correct Answer is:
A

`(t_(1//2))_(x) =tau_(y)=(ln(2))/lambda_(x)=1/lambda_(y)`
`rArr lambda_(y)=lambda_(x)/(ln(2))`
As, `lambda_(y) gt lambda_(x)`
The rate of decay of Y is greater than that of X.
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