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Assume that a neutron breaks into a prot...

Assume that a neutron breaks into a proton and an electron. The energy released during this process is (mass of neutron = `1.6725 xx 10^(-27)` kg, mass of proton = `1.6725 xx 10^(-27) kg`, mass of electron `= 9 xx 10^(-31) kg)`

A

5.4 MeV

B

0.51 MeV

C

7.10 MeV

D

6.30 MeV

Text Solution

Verified by Experts

The correct Answer is:
B

Energy `=Deltamc^(2)`
`=(m_(p) xx m_(n)) (3 xx 10^(8))^(2)`
`=m_(e) xx 9 xx 10^(16)= 9 xx 10^(-31) xx 9 xx 10^(16)` J
`=(81 xx 10^(-15))/(1.6 xx 10^(-19)) eV = 50.625 xx 10^(4)` eV
`=0.50626 xx 10^(6)` eV = 0.51 MeV
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Assume that a neutron breaks into a proton and an electron . The energy reased during this process is (mass of neutron = 1.6725 xx 10^(-27) kg mass of proton = 1.6725 xx 10^(-27) kg mass of electron = 9 xx 10^(-31) kg )

A neutron breaks into a proton and electron. Calculate the energy produced in this reaction in MeV. Mass of an electron =9xx10^(-11) kg. mass of proton=1.6725xx 10^(-27) kg, Mass of neutron=1.6747 xx10^(-27) kg. speed of light = 3xx10^(8)m//sec .

A neutron break into proton and electron. Calculate the energy produced in this reactions in MeV. ( m_e=9.1xx10^(-31)kg, m_p=1.6725xx10^(-27) kg , m_n=1.6747xx10^(-27) kg ) :-

The mass of 1 mole of neutrons (m_(n) = 1.675 xx 10^(-27) kg) is:

A neutron breaks into a proton and electorn. Calculate the eenrgy produced in this reaction in m_(e) = 9 xx 10^(-31) kg, m_(p) = 1.6725 xx 10^(-27) kg, m_(n) = 1.6747 xx 10^(-27) kg, c = 3xx10^(8)m//sec .

Calculate the equivalent energy of electrons and proton at rest. Given that mass of electron =9.1xx10^(-31)kg and mass of proton =1.673xx10^(-27)kg .

The kinetic energy of an electron is 4.55 xx 10^(-25)J . Calculate the wavelength . [h = 6.6 xx 10^(-34)Js , mass of electron = 9.1 xx 10^(-31)kg]

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