The mass defect of `He_(2)^(4)` He is 0.03 u. The binding energy per nucleon of helium (in MeV) is

Options

A. 2.793
B. 69.825
C. 6.9825
D. 27.93

Answer

C

Explanation

The relation for the binding energy when the mass is expressed in kilograms
B.E = `Deltamc^(2)`
The relation for the binding energy when the mass is expressed in amu
B.E. `=(Deltam xx 931)`
B.E. `=0.03 xx 931 = 27.93` MeV
Binding energy per nucleon = B.E. / total nucleon
`=27.93/4 = 6.9825` MeV