Two deuterons udnergo nuclear fusion to form a Helium nucleus. Energy released in this process is : (given binding energy per nucleon for deuteron = 1.1 MeV and for helium = 7.0 MeV)

Options

A. 30.2 MeV
B. 32.4 MeV
C. 23.6 MeV
D. 25.8 MeV

Answer

C

Explanation

The fission of two deuterons is given by
`""_(1)He^(2) + ""_(1)H^(2) to ""_(2)He^(4)`
Total binding energy of two deuterium nuclei
`=1.1 xx 4 = 4.4` MeV
Binding energy of `(""_(2)He^(4))` nuclei `=4 xx 7=28` MeV
Energy released `=(B.E.)_("product") -(BE)_("reactant")`
=28-4.4
=23.6 MeV