Home
Class 12
PHYSICS
Is free neutron a stable particle ? If n...

Is free neutron a stable particle ? If not, what is its mode of decay?

A

If both assertion and reason are correct and reason is a correct explanation o f the assertion.

B

If both assertion and reason are correct but reason is not the correct explanation o f assertion.

C

If assertion is correct but reason is incorrect.

D

If assertion is incorrect but reason is correct

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • NUCLEI

    MODERN PUBLICATION|Exercise COMPETITION FILE (MATCHING TYPE QUESTIONS)|1 Videos

  • NUCLEI

    MODERN PUBLICATION|Exercise COMPETITION FILE (MATRIX MATCH TYPE QUESTIONS)|2 Videos

  • NUCLEI

    MODERN PUBLICATION|Exercise COMPETITION FILE (MULTIPLE CHOICE QUESTIONS BASED ON A GIVEN PASSAGE/COMPREHENSION)|8 Videos

  • MOVING CHARGES AND MAGNETISM

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|13 Videos

  • RAY OPTICS AND OPTICAL INSTRUMENTS

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|14 Videos

Similar Questions

Explore conceptually related problems

A free neutron decays spontaneously into

A free neutron decays to a proton but a free proton does not decay to a neutron. This is because

Neutron is a fundamental particle carrying

The figure shows a plot of number of neutron (N) versus number of protons (z) in all stable nuclei found in nature. What kind of decay are nuclei X,Y and Z expected to show?

A free neutron decays into a proton, an electron and

Assertion: In the process of nuclear fission, the fragments emit two or three neutrons as soon as they are formed and subsequently emit particles. Reason : As the fragments contain an excess of neutrons over protons, emission of neutrons and particles bring their neutron/proton ratio the to stable values

The least stable free radical is

Consider the decay of a free neutron at rest: n top+e^(-) Show that the tow-body dacay of this type must necessarily give an electron of fixed energy and, therefore, cannot for the observed continous energy distribution in the beta -decay of a neutron or a nucleus.