What is the nuclear radius of`Te^(125)` in fermi if that of `Al^27` is 3.6 fermi?

Explanation

To find the nuclear radius of Tellurium-125 (Te-125) given that the nuclear radius of Aluminium-27 (Al-27) is 3.6 fermi, we can use the formula for nuclear radius:

\[ R = R_0 A^{1/3} \]

where:
- \( R \) is the nuclear radius,
- \( R_0 \) is a constant (approximately 1.2 fermi),
- \( A \) is the mass number.
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