Home
Class 12
PHYSICS
The frequency (n)of vibration of a strin...

The frequency `(n)`of vibration of a string is given as `n=(1)/(2l)sqrt(T/(m)),` where `T` is tension and `l` is the length of vibrating string, then the dimensional formula for `m` is :

A

`[M^(0)L^(1)T^(1)]`

B

`[M^(0)L^(0)T^(0)]`

C

`[M^(1)L^(-1)T^(0)]`

D

`[ML^(0)T^(0)]`

Text Solution

Verified by Experts

The correct Answer is:
C
`n=(1)/(2l)sqrt((T)/(m)):.n^(2)=(1)/(4l^(2))(T)/(m)`
`m=(T)/(4l^(2).n^(2))=(MLT^(-2))/(L^(2)xxT^(-2))=[ML^(-1)]`
Hence correct choice is `(c )`.
Promotional Banner

Topper's Solved these Questions

  • UNITS, MEASURMENTS, DIMENSIONS, ERRORS OF MEASUREMENTS

    MODERN PUBLICATION|Exercise Multiple Choice Questions (Level-II)|47 Videos

  • UNITS, MEASURMENTS, DIMENSIONS, ERRORS OF MEASUREMENTS

    MODERN PUBLICATION|Exercise Multiple Choice Questions (Level-III)|6 Videos

  • UNIT TEST PAPER NO.4

    MODERN PUBLICATION|Exercise MCQ|31 Videos

  • WAVE MOTION

    MODERN PUBLICATION|Exercise RECENT COMPETITIVE QUESTIONS|18 Videos

Similar Questions

Explore conceptually related problems

Instead of M, L and T, let c, G and h be the quantities, then dimensions of M and L are

The transverse displacement of a string is given by y ( x , t ) = 0.06 sin ((2pi)/(3)) x cos ( 120 pi t) where 'x' & 'y' are 'm' and 't' is s. The length of the string is 1.5m and its mass is 3.0 xx 10^(-2) kg . Determine the tension in the string.

The transverse displacement of a string is given by y ( x , t ) = 0.06 sin ((2pi)/(3)) x cos ( 120 pi t) where 'x' & 'y' are 'm' and 't' is s. The length of the string is 1.5m and its mass is 3.0 xx 10^(-2) kg . Interpret the wave as a superposition of two waves travelling in opposite direction. What is the wavelength, frequency and speed of each wave?

The transverse displacement of a string is given by y ( x , t ) = 0.06 sin ((2pi)/(3)) x cos ( 120 pi t) where 'x' & 'y' are 'm' and 't' is s. The length of the string is 1.5m and its mass is 3.0 xx 10^(-2) kg . Does the function represent a travelling wave or stationary wave ?

The tension of a stretched string is increased by 69%. In order to keep its frequency of vibration constant, its length must be increased by

A quantity x is given by espilon_(0)L(DeltaV)/(Deltat) where espilon_(0) is permittivity of free space L is length, DeltaV is a potential difference and Deltat is the time interval. The dimensional formula for x is the same as that of :