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In the relation y=rsin (omegat-kx) the d...

In the relation `y=rsin (omegat-kx)` the dimensions of `(omega)/(k)` are :

A

`[M^(0)L^(0)T^(0)]`

B

`[M^(0)L^(1)T^(-1)]`

C

`[M^(0)L^(0)T^(1)]`

D

`[M^(0)L^(1)T^(0)]`

Text Solution

Verified by Experts

The correct Answer is:
B
`y=rsin(omegat-kx)`
Here `omegat=angle:.omega=(1)/(T)=T^(-1)`
Similarly `kx`=angle`impliesk=(1)/(L)=L^(-1)`
`:.(omega)/(k)=(T^(-1))/(L^(-1))=LT^(-1)`
or Simply `(omega)/(k)` represent wave velocity as
`(omega)/(k)=(2piv)/(2pi//lambda)=vlambda`
Hence correct choice is `(b)`.
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