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The dimensions of the quantity namely (m...

The dimensions of the quantity namely `(mu_(0)ce^(2))/(2h)` is : where `mu_(0)-` permebility of free space, `c`-velocity of light, `e`=electron charge and `h` being Plank's constant :

A

`[M^(0)LT]`

B

`[M^(0)L^(0)T]`

C

`[M^(0)L^(0)T^(0)]`

D

`[M^(-2)L^(-1)T^(3)]`

Text Solution

Verified by Experts

The correct Answer is:
C
Here let `X=(mu_(0)Ce^(2))/(2h)`
Putting the dimensions of various quantities we get
`X=[MLT^(-2)A^(-2)]xx[M^(0)L^(1)T^(-1)]xx[A^(2)T^(2)]`
`=[M^(0)L^(0)T^(0)]xx[M^(-1)L^(-2)T]`
Thus `(c )` is the correct choice .
`:.` Correct choice is `(c )`
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