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The relative density of a material of a ...

The relative density of a material of a body is found by weighing it first in air and then in water. If the wt. of the body in air is `W_(1)=8*00+-0*05` newton and weight in water is `W_(2)=6*00+-0*05` newton. Then the relative density, `p_(r)=(W_(1))/(W_(1)-W_(2))` with the maximum permissible error is :

A

`4*00+-0*62%`

B

`4*00+-0*82%`

C

`4*00+-3*2%`

D

`4*00+-5*62%`

Text Solution

Verified by Experts

The correct Answer is:
D
Relative density, `rho_(r)=(W_(1))/(W_(1)-W_(2))`
`=(8*00)/(8*00-6*00)=4*00`
`(Deltarho_(r))/(rho_(r))xx100=(DeltaW_(1))/(W_(1))xx100+(Delta(W_(1)-W_(2)))/(W_(1)-W_(2))xx100`
`=(0*05)/(8*00)xx100+(0*05+0*05)/(2)xx100`
`5.62%`
`:.rho_(r)=4*00+-5*62%`
Hence correct choice is `(d)`.
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