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The least count of a stop watch is 1//5 ...

The least count of a stop watch is `1//5` second. The time of `20` oscillations of a pendulum is measured to be `25` seconds. The minimum percentage error in the measurement of time will be :

A

`0*1%`

B

`0*8%`

C

`8%`

D

`1.8%`

Text Solution

Verified by Experts

The correct Answer is:
B
Here `T=25` seconds, `DeltaT=(1)/(5)`Seconds
`:.(DeltaT)/(T)xx100=(1/5)/(25)xx100=0*8%`
So the correct choice is `(b)`.
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