The resistance of a metal is given by `R=(V)/(I),` where `V` is potential difference and `I` is the current. In a circuit the potential difference across resistance is `V=(8+-0*5)` `V` and current in resistance, `I=(4+-0*2)A`. And current in resistance with its percentage error :

Options

A. `(2+-5*6%)` ohm
B. `(2+-0*7%)` ohm
C. `(2+-35%)` ohm
D. `(2+-11*25%)` ohm

Answer

D

Explanation

`R=(V)/(I)=(8)/(4)=2ohm.`
`(DeltaR)/(R)xx100=(DeltaV)/(V)xx100+(DeltaI)/(I)xx100`
`=(0*5)/(8)xx100+(0*2)/(4)xx100=11*25%`
`:.R=(2+-11*25)Omega.`
Hence correct choice is `(d)`.