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What is the unit of k in the relation ...

What is the unit of `k` in the relation
`U=(ky)/(y^(2)+a^(2))`
where `U` represents the potential energy, `y` represents the displacement and `a` represents the maximum displacement `i.e.,` amplitude ?

A

`ms^(-1)`

B

ms

C

Jm

D

`Js^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
Here `k=(U[y^(2)+a^(2)])/(y)=(Jm^(2))/(m)=Jm.`
Hence correct choice is `(c )`.
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