The radius of nucleus is `R=R_(0)A^(1//3)`where `A` is the mass number of the atom. What are the dimensions of `R_(0)` ?

Options

A. `[M^(0)L^(0)T^(-1)]`
B. `[M^(0)LT^(0)]`
C. `[ML^(2)T^(-2)]`
D. `[M^(0)L^(0)T^(0)]`

Answer

B

Explanation

Here `R=R_(0)A^(1//3)`
`R_(0)=(R)/(A^(1//3))=(L^(1))/([M^(0)L^(0)T^(0)]^(1//3))`
`=[M^(0)L^(1)T^(0)]`
Hence correct choice is `(b)`.