`B^(2)/(mu_(0)),` where `B` is magnetic induction and `mu_(0)` is permeability of free space, has the same dimensions as :

Options

A. that of energy
B. that of presssure
C. that of energy density
D. power

Answer

C

Explanation

`X=(B^(2))/(2mu_(0))=([ML^(0)T^(-2)A^(-1)]^(2)]/([ML^(1)T^(-2)A^(-2)])`
`=ML^(-1)T^(-2)=` Energy density
Thus `(c )` is correct choice.