If the energy of a photon of light is given by `E=kh^(x)c^(y)lambda^(z),` where `h`= Planck's constant, `c` = velocity of light and `lambda` = wavelength then values of `x,y,z` in order are :

Options

A. `1,2,1`
B. `1,1,1`
C. `1,-1,1`
D. `1,1,-1`

Answer

D

Explanation

`E=h^(x)c^(y)lambda^(z)`
Putting the dimensions
`ML^(2)T^(-2)=[ML^(2)T^(-1)]^(x)[L^(1)T^(-1)]^(y)[L^(1)]^(z)`
`[ML^(2)T^(-2)]=M^(x)L^(2x+y+z)T^(-x-y)`
`:.`Comparing the dimensions
`x=1|{:(2x+y+z=1),(2+1+z=2),(z=-1):}||{:(-x-y=-2),(-1-y=-2),(y=1):}|`
`:.`Correct choice is `(d)`.