In the formula `X=3YZ^(2),X` and `Z` have the dimensions of capacitance and magnetic induction respectively. The dimensions of `Y` in `MKS` system are :

Options

A. `M^(-2)L^(-2)T^(4)Q^(4)`
B. `M^(-3)L^(0)T^(4)Q^(-3)`
C. `M^(-3)L^(-2)T^(4)Q^(4)`
D. `M^(-3)L^(2)T^(4)Q^(-4)`

Answer

C

Explanation

Here `x=3yz^(2)`
Nero `y=(x)/(3z^(2))`
`y=("Capacitance")/(("magnetic induction")^(2))`
`y=(M^(-1)L^(-2)T^(4)A^(2))/([ML^(0)T^(-2)A^(-1)]^(2))`
`=M^(-3)L^(-2)T^(4).(A^(2)T^(2))^(2)`
`=M^(-3)L^(-2)T^(4)Q^(4)`
`:. (C )` is the correct choice.