If `D` represents the diameter,`rho` the density , `v` the speed and `eta` the coefficient of viscosity , then the quantity `(Drhov)/(eta)` has :

Options

A. dimensions of mass
B. dimensions of length
C. dimensions of time
D. no dimensions.

Answer

D

Explanation

Here quantity `=(Drhov)/(eta)`
Putting the dimensions, we have
quantity `=(L^(1)M^(1)L^(-3)L^(1)T^(-1))/(M^(1)L^(-1)T^(-1))`
`=[M^(0)L^(0)T^(0)]`
`:.(d)` is correct