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What is the unit of k in the relation ...

What is the unit of `k` in the relation
`U=(ky)/(y^(2)+a^(2))`
where `U` represents the potential energy, `y` represents the displacement and `a` represents the maximum displacement `i.e.,` amplitude ?

A

power

B

couple

C

joule- metre

D

newton- sec.

Text Solution

Verified by Experts

The correct Answer is:
C
Here `E_(p)=(kx)/(x^(2)+a^(2))`
`:.k=(E_(p)(x^(2)+a^(2)))/(x)`
`("joule" xx m^(2))/(m)`
`:.(c )` is correct .
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