For the equation `FpropA^(a)v^(b)d^(c),` where `F` is the force, `A` is the area,`v` is the velocity and `d` is the density, the values of `a,b` and `c` are respectively :

Options

A. `1,2,1`
B. `2,1,1`
C. `1,1,2`
D. `0,1,1`

Answer

A

Explanation

Taking the dimensions of both sides
`[MLT^(-2)]=[L^(2a)][L^(b)T^(-b)][M^(c)L^(-3c)]`
`=M^(c)L^(2a+c-3c)T^(-b)`
`:.c=1|{:(2a+b-3c=1),(2a=-2+3+1),(a=1):}|{:(-b=-2),(b=2):}`
Hence `FxxA^(1)v^(2)d^(1)`