If the error in the measurement of momentum of a particle is `(+100%),` then the error in the measurement of kinetic energy is :

Options

A. `250%`
B. `200%`
C. `300%`
D. `400%`

Answer

C

Explanation

Relation between `E_(k)` and `p` is `E_(k)=(p^(2))/(2m).` When `p` is doubled, `E_(k)` becomes four times. So, `E_(k)` increases by `300`.
`:.%` age increase `=(4E_(k)-E_(k))/(E_(k))xx100`
`=300%`
Hence `(c )` is correct.