The heat generated in a circuit is given by `Q=I^(2)Rt,` where `I` is current, `R` is resistance and `t` is time. If the percentage errors in measuring `I,R` and `t` are `2%,1%` and `1%` respectively, then the maximum error in measuring heat will be :

Options

A. `2%`
B. `3%`
C. `4%`
D. `6%`

Answer

D

Explanation

Here `Q=I^(2)Rt`
`:.(dQ)/(Q)xx100=2(dI)/(I)xx100+(dR)/(R)xx100+(dt)/(t)xx100`
`2xx2%+1%+1%`
Hence `(d)` is correct.