A body acted upon by a variable force F = 3 +0.5.x. Work done in moving the body from x=0 to x = 4m is:

Options

A. 8 J
B. 32 J
C. 24 J
D. 16 J

Answer

d

Explanation

Work done, `W=int_(0)^(4)(3+0.5 x)dx`
`=3int_(0)^(4)dx+0.5int_(0)^(4)xdx`
`=3[x]_(0)^(4)+0.5[(X^(2))/(2)]_(0)^(4)=3(4-0)+0.5[(16)/(2)-0]`
=16 J