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A bomb of 12 kg explodes into two parts ...

A bomb of 12 kg explodes into two parts 4 kg and 8 kg. The velocity of 8 kg mass is 6 `ms^(-1)`.The the other is :

A

4.8 J

B

288 J

C

48 J

D

24 J

Text Solution

Verified by Experts

The correct Answer is:
b

Initial momentum= Final momentum.
`12xx0=8xx6+4v`
`implies v=-12 ms^(-1)`
`:. K.E=(1)/(2)4(-12)^(2)=288 J`
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