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The momentum of body decreases by 20% Th...

The momentum of body decreases by 20% The percentage decrease in kinetic energy of the body is :

A

0.36

B

0.24

C

0.12

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
a
`p.=p-(20)/(100)p=4/5p`
When momentum becomes n times then % change in
`K.E=(n^(2)-1)xx100`
=`[(4/3)^(2)-1]xx100=((16)/(25)-1)xx100=-36%`
-ve sign show that energy decreses by 36%.
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Knowledge Check

  • The momentum of a body increases by 20%. What is the percentage increase in its K.E.?

    A
    60
    B
    52
    C
    44
    D
    36

  • If the linear momentum of a body is increased by 50%, then the kinetic energy of that body increases by :

    A
    2.25
    B
    0.25
    C
    1
    D
    1.25

  • If the linear momentum of a body is increased by 50% then the kinetic energy of that body increases by

    A
    `10%`
    B
    `125%`
    C
    `225%`
    D
    `25%`

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