A ball is dropped from a height 'h'. If the coefficient of restitution is 'e', the height to which the ball rise after the nth rebound is:

Options

A. `h.e^(n)`
B. `h//e^(2n)`
C. `e^(2n)//h`
D. `h.e^(2n)`

Answer

d

Explanation

We know that `e=(v_(1))/(v_(0))=(v_(2))/(v_(1))=(v_(3))/(v_(2))=…........=(v_(0))/(v_(n-1))`
`:. e^(n)=(v_(1))/(v_(0))xx(v_(2))/(v_(1))xx(v_(3))/(v_(2))xx…xx(v_(n))/(v_(npm1)).toe^(n)-(v_(n))/(v_(0))`
`:. E^(n)=(sqrt(2ghn))/(sqrt(2gh))implies e^(2n)=(h_(n))/(h)impliesh_(n)=e^(2n)h`