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A body is dropped from a certain height....

A body is dropped from a certain height. At the instant it loses P.E.U. It acquires a velocity 'v' the mass of the body is :

A

`U^(2)//2V`

B

`2V//U`

C

`2V//U^(2)`

D

`2U//V^(2)`

Text Solution

Verified by Experts

The correct Answer is:
d

Gain in K.E. = loss in p.E.
`:. 1/2mv^(2)=U`
`:. M=(2U)/(V^(2))`
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