A man of 55 kg is holding a bucket of mass 25 kg. He walks 50 m on a level road at a constant speed of 3 ms" and then climbs up a hill of height 20 m. What is the work done by the man ?

Options

A. 16 KJ
B. 12 KJ
C. 3.5 KJ
D. 2 KJ

Answer

a

Explanation

While walking work done is zero as force and displacement are `bot` to each other and there is no net force along horizontal as the speed is constant.
`:.` work is done in climbing the hill.
`W=(M+m)gh=(55+25)xx10xx20=16000 J`
= 16 J