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A body of mass 10 kg is raised to height...

A body of mass 10 kg is raised to height 10 m above the ground with an acceleration of `1.5 m//s^(2)`. The work done in this case taking `g = 10 ms^(-2)` is:

A

1000 J

B

1100 J

C

1150 J

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
c
F-mg=ma
F=m(g+a)

Work done, `W=m(g+a)xxh`
`10xx(10+1.5)xx10=1150 J`
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