Speeds of two indentical cars are u and 4u at a specific instant. The ratio of the respective distances in which the two cars are stopped from that instant is :

Options

A. `1:1`
B. `1:4`
C. `1:8`
D. `1:16`

Answer

d

Explanation

Stopping distance=`(K.E.)/("Force of resistance")`
`S=(1/2mv^2)/(mu mg)=(v^2)/(2mug)`
Here, `(S_(1))/(S_2)=(u^2)/((4u)^2)=(1)/(16)`.