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A force vecF=(5hati+3hatj+2hatk)N is app...

A force `vecF=(5hati+3hatj+2hatk)N` is applied over a particle which displaces it from its origin to the point `vecr=(2hati-hatj)` m. The work done on the particle in joules is :

A

-7

B

`+7`

C

`+10`

D

`+13`

Text Solution

Verified by Experts

The correct Answer is:
b

Here, `W=vecF.vecS`
=`(5hati+3hatj+2hatk).(2hati-hatj)`
=10-3=7 J.
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