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A bullet fired into a fixed target loses...

A bullet fired into a fixed target loses half of its velocity after penetrating 3 cm. How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion ?

A

3.0 cm

B

2.0 cm

C

1.5 cm

D

1.0 cm

Text Solution

Verified by Experts

The correct Answer is:
d
Let K be the initial kinetic enrgy and f be the resistive force.
`DeltaK`= work done against f.
`1/2m[v^2-(v^2)/(4)]=fxx3`
`1/2m[(v^2)/(4)-0]=fxx x`
Dividing `([1-1/4])/(1/4)=3/x` or x=1 cm.
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