If the momentum of a body increases by 0-01%, its kinetic energy will increase by:

Options

A. 0-0%
B. 0.0002
C. 0.0004
D. 0.0008

Answer

b

Explanation

Here,the relation between K.E. and momentum is:
`E=(p^2)/(2m)`
`(DeltaE)/(E)=(2Deltap)/(p)` (`because` m is constant)
`%(DeltaE)/€=2xx(0.01)/(1)=0.02%`