A cricket ball having a mass of 0.15 kg is moving with uniform speed of 126 km/h strikes the bat of the player at its middle who holds it firmly at its position. After hitting the bat the ball moves straight back along the same path. If the collision is assumed to be perfectly clastic and bat and ball remain in contact only for a small fraction of time 0.001s the force that batsman has to apply to hold the ball for that short interval would be:

Options

A. 105 N
B. 10.5 N
C. 1.05 X `10^4 N`
D. 1050N

Answer

c

Explanation

Here F = Rate of change of momentum
=`(2mv)/(t)=(2xx0.15xx35)/(0.001)`
=`(70xx15xx10^3)/(100xx1)`
=`1.50xx10^4`