A runner weighing 60 kg raises the CG of his body by 0.25 m during each step of 1 min length. If he runs for 6 km and there is loss of 10% of the energy due to friction of air etc. What is the total energy required by him from his intake of food ?

Options

A. `9xx10^(5)` J
B. `8xx10^(5)` J
C. `9.9xx10^(5)` J
D. `8.8xx10^(5)` J

Answer

c

Explanation

Here in taking a run of 6000 metre, there are 6000 steps.
For each step he raise the C.G. by 0.25 m
`:.` P.E. required by the runner
`E_P=60xx10xx0.25xx6000`
=`9xx10^5J`
Total energy required
=`(9xx10^5xx110)/(100)=9.9xx10^5 J`