A ball is allowed to fall from a height of 10 m. There is 40% loss of energy every time it hits the ground. After second impact with the ground, the ball will rise upto

Options

A. 10 m
B. 6 m
C. 3.6 m
D. 2.4 m

Answer

c

Explanation

Here let `h_1` and `h_2` be the heights to which the ball rise.
Then `h_1 prop P.E`
`:. H_1=(60)/(100)xx10=6m`
Similarly `h_2=(60)/(100)xx6=3.6 m`