Home
Class 12
PHYSICS
If two springs S, and S, of force consta...

If two springs S, and S, of force constants k, and ky, respectively, are stretched by the same force, it is found that more work is done on spring S, than on spring S.
Statement 1: If stretched by the same amount, work done on S, will be more than that on S.
Statement 2: `k_1` lt`k_2`

A

Statement 1 is true, Statement 2 is true, Statement 2 is not the correct explanation of Statement 1.

B

Statement 1 is false, Statement 2 is true.

C

Statement 1 is true, statement 2 is false.

D

Statement 1 is true, statement 2 is true, statement 2 is the correct explanation of statement 1.

Text Solution

Verified by Experts

The correct Answer is:
a

`k_1x_1=k_2x_2=F`
`w_1=1/2k_1x_1^2=((k_1x_1)^2)/(2k_1)=(F^2)/(2k_1)`
Similarly, `w_2=(F^2)/(2k_2)`
`implies w prop 1/k`
`k_1ltk_2 :. W_1gtw_2`
Statement 2 is true.
Statement `1:w_1=1/2k_1x^2`
`w_2=1/2k_2x^2`
`implies w prop k`
`because k_2gtk_1`
`:. w_2gtw_1`
`:.` Statement 1 is false.
Promotional Banner

Topper's Solved these Questions

  • WORK , POWER , ENERGY AND COLLISIONS

    MODERN PUBLICATION|Exercise Recent Competitive Questions|8 Videos
  • WORK , POWER , ENERGY AND COLLISIONS

    MODERN PUBLICATION|Exercise Revision Test|40 Videos
  • WORK , POWER , ENERGY AND COLLISIONS

    MODERN PUBLICATION|Exercise Multiple Choice Questions (LEVEL-II)|67 Videos
  • WAVE OPTICS

    MODERN PUBLICATION|Exercise Recent Competitive Questions|18 Videos

Similar Questions

Explore conceptually related problems

Two springs having their force constants k_1 and k_2 are stretched through same distance. Ratio of their energies P.E_1 , and P.E_2 is

If k is the force constant of the spring and mu is the coefficient of friction between the body of mass m and the floor, then write the total negative work done on the body tied to a spring at one end and the other end of the spring to a rigid support.