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When a sphere of moment of inertia I mov...

When a sphere of moment of inertia I moves down an inclined plane, the percentage of energy which is rotational, is approximately :

A

`100%`

B

`72%`

C

`28%`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
T.E. = Linear K.E. + Rot. K.E.
`=(1)/(2)mv^(2)+(1)/(2)Iomega^(2)`
`=(1)/(2)mv^(2)+(1)/(2).(2)/(5)mr^(2)omega^(2)=(1)/(2)mv^(2)+(1)/(5)mv^(2)`
`=(7)/(10)mv^(2)=(7)/(10)xx50xx25=875ergs`
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