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A thin uniform rod of length 2l is acted...

A thin uniform rod of length 2l is acted upon a constant torque. The angular velocity changes from zero to `omega` in time t. The value of torque is :

A

`(ml^(2)omega)/(t)`

B

`(ml^(2)omega)/(12t)`

C

`(ml^(2)omega)/(3t)`

D

`(2ml^(2)omega)/(t)`

Text Solution

Verified by Experts

The correct Answer is:
C
`I=(1)/(12)M(2l)^(2)=(1)/(3)Ml^(2)`
`alpha=(omega-0)/(t)=(omega)/(t)`
Now `tau=Ixxalpha=(1)/(3)(Ml^(2)omega)/(t)`
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