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Speed of a solid sphere after rolling do...

Speed of a solid sphere after rolling down an inclined plane is :

A

`((10)/(7)gh)^(1//2)`

B

`sqrt((6)/(5)gh)`

C

`sqrt((4)/(5)gh)`

D

`(gh)^(1//2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Total K.E. of rolling sphere `=(7)/(10)mv^(2)`
`therefore (7)/(10)mv^(2)=mgh" "v=sqrt((10)/(7)gh)`
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